Dice Roll Program in Java with Source Code

In this post, I will be sharing a simple Dice Roll Program in Java. Dice is a cube that has between one and six numbers or spots on its sides to provide random numbers. In other words, a dice can produce the integer numbers in the range 1(inclusive) and 6(inclusive).

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Here in this program, we are getting the number of dice to be rolled from the user input.

Dice Roll Program in Java

Let's understand the problem with some examples:

Example 1

 Enter the number of Dice to be rolled: 2
3 2 

Example 2

 Enter the number of Dice to be rolled: 7
3 6 2 4 2 6 1 

Java Program

Below is the Java program for rolling Dice:

 import java.util.Scanner;
import java.util.Random;

public class DiceRoll 
{
    public static void main(String args[]) 
    {
      System.out.print("Enter the number of Dice to be rolled: ");
      // Initializing Scanner object to read input from user      
      Scanner scan = new Scanner(System.in);
      // Reading the number of Dices to be rolled
      int numberOfDice = scan.nextInt();
      /* Creating Random class object to generate
      random numbers */
      Random randomNumber = new Random();
      for(int i=0;i < numberOfDice; i++)
      {
        System.out.print(randomNumber.nextInt(6)+1);
        System.out.print(" ");
      }
    }
}

Output:
Enter the number of Dice to be rolled: 4
3 6 1 5

Explanation

According to Oracle docs, the Random class nextInt(int) method returns a pseudorandom, uniformly distributed int value between 0 (inclusive) and the specified value (exclusive).

 randomNumber.nextInt(6)+1

In the above code, nextInt(6) will return a random integer number between 0 and 5, but we need it from 1 to 6. That's why we need to add 1 to the nextInt(6) statement.

That's all for today. Please mention in the comments if you have any questions related to the dice roll program in java with source code.