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What are Unary operators?
Unary operators are those operators which require a single operand.Syntax
!(operand)
Examples of ! in Java
public class UnaryNotOperator { public static void main(String args[]) {
// initializing variables int a = 100, b = 10; boolean visible = true;
// Printing variable values System.out.println("Is visible: " + visible); System.out.println("a: "+ a + " b: " + b);
// Using unary operator ! System.out.println("Is visible: "+ !visible); System.out.println(" !(a > b) : " + !(a > b)); System.out.println(" !(a < b) : " + !(a < b));
} }
Output:
Is visible: true
a: 100 b: 10
Is visible: false
!(a > b) : false
!(a < b) : true
Compiler Error
If the expression to the right of the ! operator doesn't evaluate to a boolean, then it will throw a compiler error 'bad operand type for unary operator' as shown below: public class UnaryNotOperator2 {
public static void main(String args[]) {
// initializing variables a and b
int a = 1, b = 10;
// Printing variable values
System.out.println("a: "+ a + " b: " + b);
// Using unary operator !
System.out.println(" !(a + b) : " + !(a + b));
}
}
Output:
/UnaryNotOperator2.java:10: error: bad operand type int for unary operator '!'
System.out.println(" !(a + b) : " + !(a + b));
^
1 error
Explanation:
The cause of this error is that (a+b) is a numeric expression that will return an integer value. We all know ! is a unary operator and it expects a boolean value. Since (a+b) expression is evaluating to int and ! operator is expecting boolean, so the above code is giving the compilation error.Equality operator !=
This operator is pronounced as not equal to operator. I have explained this in detail here.That's all for today, please mention in the comments in case you have any questions related to the what does ! operator mean in Java with examples.